C06-6.mws

COMPLEX ANALYSIS: Maple Worksheets, 2001
(c) John H. Mathews Russell W. Howell
mathews@fullerton.edu howell@westmont.edu

Complimentary software to accompany the textbook:

COMPLEX ANALYSIS: for Mathematics & Engineering, 4th Ed, 2001, ISBN: 0-7637-1425-9
Jones and Bartlett Publishers, Inc., 40 Tall Pine Drive, Sudbury, MA 01776
Tele. (800) 832-0034; FAX: (508) 443-8000, E-mail: mkt@jbpub.com, http://www.jbpub.com/


CHAPTER 6 COMPLEX INTEGRATION

Section 6.6 The Theorems of Morera and Liouville and Some Applications

In this section we investigate some of the qualitative properties of analytic and harmonic functions. Our first result shows that the existence of an antiderivative for a continuous function is equivalent to the statement that the integral of f is independent of the path of integration. This result is stated in a form that will serve as a converse to the Cauchy-Goursat theorem.

Theorem 6.13 (Morera Theorem) Let f(z) be a continuous function in a simply connected domain D.

If int(f(z),z = C .. ` `) = 0 for every closed contour in D, then f(z) is analytic in D.

Cauchy's integral formula shows how the value f(z[0]) can be represented by a certain contour integral. If we choose the contour of integration C to be a circle with center z[0] , then we can show that the value f(z[0]) is the integral average of the values of f(z) at points z on the circle C .

Theorem 6.14 (Gauss's Mean Value Theorem)

If f(z) is analytic in a simply connected domain D that contains the circle C: abs(z-z[0]) = R , then

f(z[0]) = 1/(2*pi) int(f(z[0]+R*exp(i*theta)),theta = 0 .. 2*pi) .

Theorem 6.15 (Maximum Modulus Principle)

Let f(z) be analytic and nonconstant in the domain D. Then abs(f(z)) does not attain a maximum value at any point z[0] in D.

We sometimes state the maximum modulus principle in the following form.

Theorem 6.16 (Maximum Modulus Principle)

Let f(z) be analytic and nonconstant in the bounded domain D. If f is continuous on the closed region R that consists of D and all of its boundary points B , then abs(f(z)) assumes its maximum value, and does so only at point(s) z[0] on the boundary B .

Theorem 6.17 (Cauchy's Inequalities)

Let f(z) be analytic and nonconstant in the domain D that contains the circle C: abs(z-z[0]) = R .

If abs(f(z)) < M holds for all points z on C, then

abs(f^`(n)`*`(`*z[0]*`)`) <= n!*M/(R^n) for n = 1, 2, `...` .

The next result shows that a nonconstant entire function cannot be a bounded function.

Theorem 6.18, (Liouville's Theorem)

If f(z) is an entire function and f(z) is bounded for all values of z in the complex plane, then f(z) is constant.


Example 6.27, Page 256. Show that the function sin(z) is NOT a bounded function.

> i:='i': x:='x': y:='y': z:='z':
f := z -> sin(z):
`f(z) ` = f(z);
`f(x + iy) ` = f(x + I*y);
`f(x + iy) ` = evalc(f(x + I*y));
`|f(x + iy)| ` = evalc(abs(f(x + I*y)));
f(pi/2 + i*y) = evalc(f(Pi/2 + I*y));
lim := limit(f(Pi/2 + I*y), y=infinity):
print(`limit(f(pi/2 + I*y), y=infinity)`,` = `,lim);

`f(z) ` = sin(z)

`f(x + iy) ` = sin(x+I*y)

`f(x + iy) ` = sin(x)*cosh(y)+I*cos(x)*sinh(y)

`|f(x + iy)| ` = sqrt(sin(x)^2*cosh(y)^2+cos(x)^2*sinh(y)^2)

sin(1/2*pi+i*y) = cosh(y)

`limit(f(pi/2 + I*y), y=infinity)`, ` = `, infinity

We can use Liouville's theorem can be used to establish an important theorem of elementary algebra.

Theorem 6.19 (The Fundamental Theorem of Algebra)

If P(z) is a polynomial of degree n, then P(z) has at least one zero.

Corollary 6.4 Let P(z) be a polynomial of degree n. Then P(z) can be expressed as the product of linear factors. That is, P(z) = A*(z-z[1])*`...`*(z-z[2])*(z-z[n]) where z[1], z[2], `...`, z[n] are the zeros of P(z) counted according to multiplicity an A is a constant.

End of Section 6.6.